Calculation of Active Drug Moiety

The following formula may be used to calculate the active drug moiety portion of a drug compound:

$$ Drug \ Moiety \ (fraction) = {Drug\ Moiety (g/mole ) \over Drug \ compound \ (g/mole)} $$


Solved Problem: The chemical formula of methadone hydrochloride is C21H27NO.HCl

a) Calculate the molecular weights of the base and the salt form.

C21 = 21 X 12.01 = 252.21
H27 = 27 X 1 = 27
N = 1 X 14.01 = 14.01
O = 1 X 16 = 16
309.22 , MW of methadone base

H = 1 X 1 = 1
Cl = 1 X 35.45

$$ \ = {35.45 \over 36.45 }$$

309.22 + 36.45 = 345.67, MW of methadone salt

Answer: 309.22 g/mole; 345.67 g/mole

b) Calculate the fraction of active moiety in the compound.

Approach:

$$ {309.22 (g/mole) \over 345.67 (g/mole)} =0.895, fraction \ of \ methadone \ base $$

Answer: 0.895

c) Calculate the percent of active moiety in the compound.

Approach:

$$ {0.895 \times 100}=89.5 % methadone base $$

Answer: 89.5 %

d) Calculate the quantity of methadone in a 10 mg tablet of methadone hydrochloride.

Approach: .

$${10 \ mg \over 345.67 (g/mole)} = {x\ mg \over 309.22 (g/mole)} $$

Answer: 8.95 mg methadone

e) Calculate the quantity of methadone hydrochloride needed to supply a 10 mg dose of methadone.

Approach:

$${10 \ mg \over 309.22 (g/mole)} = {x \ mg \over 345.67 (g/mole)} $$

Answer: 11.18 mg methadone hydrochloride